A spring is sent into oscillation. If the displacement of the spring from its equilibrium point is measured over time what type of relationship would exist between displacement and time? a. Circular b. Parabolic c. Linear d. Sinusoidal

The correct answer is d. Sinusoidal.<br /><br />When a spring is oscillated, the displacement of the spring from its equilibrium point over time follows a sinusoidal relationship. This is because the motion of the spring is periodic and can be described by a sine or cosine function.<br /><br />The displacement of the spring from its equilibrium point can be represented by the equation:<br /><br />x(t) = A * sin(ωt + φ)<br /><br />where x(t) is the displacement at time t, A is the amplitude of the oscillation, ω is the angular frequency, and φ is the phase shift.<br /><br />The sinusoidal relationship between displacement and time is a fundamental characteristic of simple harmonic motion, which is the type of motion exhibited by a spring oscillating about its equilibrium point.