Cakulate the heat lin (W/m^2) through a plane union wall whose thickness is much less than its width and height if the will is made of steel (a=40W/(m^circ C)] The wall thickness b 6=50mm The tempentures on the wall surfaces are kept constant t_(10)=100^circ C and t_(2)=90^circ C 500 00000 8000 4000

To calculate the heat flux (W/m²) through aary wall, we can use the formula:<br /><br />q = (k * (t1 - t2)) / d<br /><br />where:<br />q is the heat flux (W/m²)<br />k is the thermal conductivity of the wall material (W/m·°C)<br />t1 and t2 are the temperatures on the two surfaces of the wall (°C)<br />d is the thickness of the wall (m)<br /><br />Given:<br />k = 40 W/(m·°C)<br />t1 = 100°C<br />t2 = 90°C<br />d = 50 mm = 0.05 m<br /><br />Substituting the values into the formula:<br /><br />q = (40 W/(m·°C) * (100°C - 90°C)) / 0.05 m<br />q = (40 W/(m·°C) * 10°C) / 0.05 m<br />q = 400 W/m²<br /><br />Therefore, the heat flux through the plane unitary wall is 400 W/m².