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What amount of heat is needed to make ice weighing 150 g, taken at a temperature e of -10^circ C , get steam at 100^circ C

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What amount of heat is needed to make ice weighing 150 g,
taken at a temperature e of -10^circ C , get steam at 100^circ C

What amount of heat is needed to make ice weighing 150 g, taken at a temperature e of -10^circ C , get steam at 100^circ C

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мастер · Репетитор 5 лет

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To calculate the amount of heat needed to make ice weighing 150 g, taken at a temperature of -10°C, get steam at 100°C, we need to consider the following steps:<br /><br />1. Heating the ice from -10°C to 0°C<br />2. Melting the ice at 0°C<br />3. Heating the water from 0°C to 100°C<br />4. Converting the water at 100°C to steam<br /><br />Let's calculate the heat required for each step:<br /><br />1. Heating the ice from -10°C to 0°C:<br /> Q1 = m * c_ice * ΔT<br /> Q1 = 150 g * 2.09 J/g°C * (0°C - (-10°C))<br /> Q1 = 313.5 J<br /><br />2. Melting the ice at 0°C:<br /> Q2 = m * L_fusion<br /> Q2 = 150 g * 334 J/g<br /> Q2 = 50100 J<br /><br />3. Heating the water from 0°C to 100°C:<br /> Q3 = m * c_water * ΔT<br /> Q3 = 150 g * 4.18 J/g°C * (100°C - 0°C)<br /> Q3 = 6270 J<br /><br />4. Converting the water at 100°C to steam:<br /> Q4 = m * L_vaporization<br /> Q4 = 150 g * 2260 J/g<br /> Q4 = 339000 J<br /><br />Now, let's calculate the total heat required:<br />Q_total = Q1 + Q2 + Q3 + Q4<br />Q_total = 313.5 J + 50100 J + 6270 J + 339000 J<br />Q_total = 394683.5 J<br /><br />Therefore, the amount of heat needed to make ice weighing 150 g, taken at a temperature of -10°C, get steam at 100°C is 394683.5 J.
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