Calculate the medial value (average)of density: hat (p)=(dot (x))/(hat (p)=(dot {x))/(kn(hat (I))^2)=(4times 1.406)/(1.15-3.14)=

It appears there is a mistake in the provided formula. Let's correct it and calculate the median value (average) of density.<br /><br />Given:<br />\[<br />\hat{p} = \frac{\dot{x}}{k n (\hat{I})^2}<br />\]<br /><br />Substitute the given values:<br />\[<br />\hat{p} = \frac{4 \times 1.406}{1.15 - 3.14}<br />\]<br /><br />First, calculate the denominator:<br />\[<br />1.15 - 3.14 = -1.99<br />\]<br /><br />Now, substitute this back into the formula:<br />\[<br />\hat{p} = \frac{4 \times 1.406}{-1.99}<br />\]<br /><br />Calculate the numerator:<br />\[<br />4 \times 1.406 = 5.624<br />\]<br /><br />Now, divide by the denominator:<br />\[<br />\hat{p} = \frac{5.624}{-1.99} \approx -2.82<br />\]<br /><br />So, the median value (average) of density is approximately:<br />\[<br />\hat{p} \approx -2.82<br />\]