Math for Practice: 1. A listener is at rest and the source is moving toward him at 30ms^-1 what is the frequency as heard by the listener?The frequency and speed of the sound is 200 Hz and 332ms^-1 [218.87 Hz]

To solve this problem, we can use the Doppler effect formula for sound:<br /><br />f' = f * (v + v_s) / (v + v_o)<br /><br />Where:<br />f' is the observed frequency<br />f is the emitted frequency<br />v is the speed of sound<br />v_s is the speed of the source<br />v_o is the speed of the observer<br /><br />Given:<br />f = 200 Hz<br />v = 332 m/s<br />v_s = -30 m/s (negative because the source is moving towards the observer)<br />v_o = 0 m/s (the observer is at rest)<br /><br />Plugging in the values, we get:<br /><br />f' = 200 * (332 + (-30)) / (332 + 0)<br />f' = 200 * 302 / 332<br />f' ≈ 182.43 Hz<br /><br />Therefore, the frequency heard by the listener is approximately 182.43 Hz.