Dare [ T=580 mathrm(~K) m=0,7 ] [ ( Mraga )=2 mathrm(kn) t=300 mathrm(~K) t=4200 mathrm(~g) mathrm(~m) ( w.yag ) ] [ ( tcu )=320 mathrm(~m) ]

It appears that the provided information is incomplete or lacks context for a specific problem. To assist you effectively, I need a clear and complete question or problem statement. However, I can provide some general guidance based on the given data.<br /><br />Given:<br />- Temperature \( T = 580 \, \text{K} \)<br />- Mass \( m = 0.7 \, \text{kg} \)<br />- Pressure \( P = 2 \, \text{kN} = 2000 \, \text{N} \)<br />- Temperature \( t = 300 \, \text{K} \)<br />- Mass \( m = 4200 \, \text{g} = 4.2 \, \text{kg} \)<br />- Volume \( V = 320 \, \text{m}^3 \)<br /><br />If you are dealing with a thermodynamic problem, such as calculating work done by a gas, we can use the ideal gas law and the first law of thermodynamics. However, without a specific question, I can only outline the general steps:<br /><br />1. **Ideal Gas Law**: \( PV = nRT \)<br /> - Where \( P \) is pressure, \( V \) is volume, \( n \) is the number of moles, \( R \) is the gas constant, and \( T \) is temperature.<br /><br />2. **First Law of Thermodynamics**: \( \Delta U = Q - W \)<br /> - Where \( \Delta U \) is the change in internal energy, \( Q \) is heat added, and \( W \) is work done by the system.<br /><br />If you have a specific question or need help with a particular calculation, please provide more details or clarify the problem statement.