In the course of the experiment, the properties of the material of a some body were in vestigated, as a result of which the average density and its absolute error were obtained bar (rho )=3.51 Delta bar (rho )=0 Please select the correct record of the final result of this experiment rho =3.51pm 0.04 rho =(3.51pm 0.04)cm rho =(3.51pm 0.04)g/cm^3 rho =(3.51pm 0.04)g/cm rho =3.510pm 0.043 rho =(3.5100pm 0.0436)g/cm^3

The correct record of the final result of this experiment is:<br /><br />$\rho =(3.51\pm 0.04)g/cm^{3}$<br /><br />Explanation: The average density of the material is given as $\bar{\rho} = 3.51$, and the absolute error is given as $\Delta\bar{\rho} = 0$. The absolute error represents the uncertainty in the measurement of the average density. In this case, the absolute error is zero, which means there is no uncertainty in the measurement of the average density.<br /><br />The final result of the experiment should include both the average density and the absolute error. The correct record of the final result should be in the form of $\rho = (3.51 \pm 0.04)g/cm^{3}$, where the average density is 3.51 and the absolute error is 0.04. The unit of density is given as $g/cm^{3}$, which represents the mass per unit volume of the material.