2) Clano [ ( Enot )=2000 mathrm(Dn) m=20 mathrm(z)=0.02 mathrm(~m) h-? ]

To solve for \( h \) in the given equation, we need to understand the context and the relationship between the variables. However, the provided information seems incomplete or unclear. Let's break down what we have:<br /><br />\[<br />\begin{array}{l}<br />\text{Enot} = 2000 \mathrm{Dn} \\<br />m = 20 \mathrm{z} = 0.02 \mathrm{~m} \\<br />h =?<br />\end{array}<br />\]<br /><br />Given the variables and their relationships, it's not immediately clear how \( h \) is related to the other variables. Let's assume there might be a typographical error or missing information. <br /><br />If we consider \( \text{Enot} \) as a force (e.g., in Newtons), and \( m \) as mass (in kilograms), we can use the equation \( F = m \cdot g \) where \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)).<br /><br />However, the equation \( m = 20 \mathrm{z} = 0.02 \mathrm{~m} \) is confusing because it equates \( m \) to both \( 20 \mathrm{z} \) and \( 0.02 \mathrm{~m} \). This suggests that \( z \) might be a unit conversion factor or another variable.<br /><br />Let's assume \( z \) is a unit conversion factor and \( m \) is the mass in kilograms. Then:<br /><br />\[ m = 20 \mathrm{z} = 0.02 \mathrm{~m} \]<br /><br />This implies \( z = 0.001 \mathrm{~kg} \).<br /><br />Now, if we use \( \text{Enot} = 2000 \mathrm{Dn} \) as a force, we can find \( h \) if we assume \( \text{Enot} \) is the weight force acting on \( m \):<br /><br />\[ \text{Enot} = m \cdot g \]<br /><br />Substitute \( m = 0.02 \mathrm{~kg} \) and \( g = 9.81 \mathrm{~m/s}^2 \):<br /><br />\[ 2000 = 0.02 \cdot 9.81 \]<br /><br />\[ h = \frac{2000}{0.02 \cdot 9.81} \]<br /><br />\[ h = \frac{2000}{0.1962} \]<br /><br />\[ h \approx 10204.64 \mathrm{~m} \]<br /><br />So, \( h \approx 10204.64 \mathrm{~m} \).<br /><br />Please verify the units and context of the problem to ensure this interpretation is correct.