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Dono: 1) [ E_(x)=2000 Omega x_(t)=2 mu=0,002 v-? ]

Вопрос

Dono:
1)
[

E_(x)=2000 Omega 
x_(t)=2 mu=0,002 
v-?

]

Dono: 1) [ E_(x)=2000 Omega x_(t)=2 mu=0,002 v-? ]

Решения

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To find the voltage \( v \), we can use Ohm's Law, which states that the voltage across a resistor is equal to the product of the current flowing through it and its resistance. Mathematically, this can be expressed as:<br /><br />\[ v = i \cdot E_x \]<br /><br />where:<br />- \( v \) is the voltage,<br />- \( i \) is the current,<br />- \( E_x \) is the electromotive force (EMF) or voltage.<br /><br />However, the problem does not provide the current \( i \). To solve for \( v \), we need the value of the current \( i \). If you can provide the current, I can help you calculate the voltage.
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