Peulure: [ Q=(mathrm(cm)(t_(2)-t_(1))=380 (mathrm(Nt))/(mathrm(hrc)) cdot 2 mathrm(kT) *(750^circ mathrm(C)-150^circ mathrm(C)). ]

To solve the given equation, let's break it down step by step:<br /><br />\[ Q = \left( \mathrm{cm} \left( t_2 - t_1 \right) = 380 \frac{\mathrm{Nt}}{\mathrm{hrc}} \cdot 2 \mathrm{kT} \cdot \left( 750^{\circ} \mathrm{C} - 150^{\circ} \mathrm{C} \right) \right. \]<br /><br />First, let's simplify the temperature difference:<br /><br />\[ 750^{\circ} \mathrm{C} - 150^{\circ} \mathrm{C} = 600^{\circ} \mathrm{C} \]<br /><br />Now, substitute this back into the equation:<br /><br />\[ Q = \left( \mathrm{cm} \left( t_2 - t_1 \right) = 380 \frac{\mathrm{Nt}}{\mathrm{hrc}} \cdot 2 \mathrm{kT} \cdot 600^{\circ} \mathrm{C} \right. \]<br /><br />Next, let's simplify the constants:<br /><br />\[ 380 \frac{\mathrm{Nt}}{\mathrm{hrc}} \cdot 2 \mathrm{kT} \cdot 600^{\circ} \mathrm{C} \]<br /><br />\[ = 380 \cdot 2 \cdot 600 \]<br /><br />\[ = 456000 \]<br /><br />So, the equation simplifies to:<br /><br />\[ Q = \left( \mathrm{cm} \left( t_2 - t_1 \right) = 456000 \cdot \mathrm{kT} \right. \]<br /><br />Therefore, the final answer is:<br /><br />\[ Q = 456000 \cdot \mathrm{kT} \]<br /><br />Note: The units and constants used in the equation are not standard, so it's important to understand the context or the specific units being used.