A periodic simple harmonic oscillator is given by: y=3sin(pi t) meters , where t is in seconds The period of the system is: a. 2s b. 0.5 s c. 2 Hz d. 3 m

The correct answer is a. 2s.<br /><br />In a simple harmonic oscillator, the period (T) is the time it takes for the system to complete one full cycle of motion. In the given equation, y = 3sin(πt), the argument of the sine function is πt. The period is the time it takes for the argument to increase by 2π, which is the period of the sine function.<br /><br />To find the period, we can set the argument equal to 2π and solve for t:<br /><br />πt = 2π<br />t = 2<br /><br />Therefore, the period of the system is 2 seconds.