A force of F=3N was acting on a point particle that has moved for S=0.5m In the direction of force. What is the work A done by the force? Please select one answer option A=3.5J A=1.5J A=4.5J A=6J

To calculate the work done by the force, we can use the formula:<br /><br />Work = Force x Displacement x cos(θ)<br /><br />where:<br />- Force is the magnitude of the force acting on the particle<br />- Displacement is the distance the particle has moved in the direction of the force<br />- θ is the angle between the force and the displacement<br /><br />In this case, the force is acting in the same direction as the displacement, so the angle θ is 0 degrees. The cosine of 0 degrees is 1.<br /><br />Substituting the given values into the formula:<br /><br />Work = 3 N x 0.5 m x cos(0°)<br />Work = 3 N x 0.5 m x 1<br />Work = 1.5 J<br /><br />Therefore, the correct answer is:<br />$A=1.5J$