8. JIOKOMOTHB Ha4HHaeT TAHYTI cocraB Macco# 2000r c ycKopeHHeN I Bcero noe3/1a 0,5M/c^2 Torna CHJIa TATH JIOKOMOTHBa: a. 1 MH c. 4 MH b. 1 KH d. 4 KH 9. Herp TO JIHHMaeT rupro c CHUIOU 100 H HarrpaBJIeHHOW BepTHKaJIbHC BBepx KaKOM CHUIOH rup nexcrBye T Ha pyky Herpa ecjin ecJIV g=10M/c^2 Macca rapn 15 KT. a. 150 H c. 50 H b. 100 H d. OH 10 TPeHNS mkada 06 non 0.8 a Macca mukacba 250 Kr . HerpoBry IIbrraercs ero neperlBHHYTb . KaKoã CHIIbI oyner HerpoBHuy: a. 200 H c. 2000 H b.2500 H d . BCë paBHO He C)TBHHET 11.Ecm THHTE Kora 3a __ XBOCT, TO npw ynpyrocTH 200H/M OH pactsuyJICAHa 8 cM,a a. 1600 H c. 16H b. 25 H d. 0,04 H 12 BynceHb IIvnceHb CWIT Ha KayeJIM,KoTopas ( HaXO)UTC B paBHOBecm .Macca Byncena 5 rpaMM H paccrosHHHe no HeHTPa Kayejin 0,1 M. Macca Ilymcerns 12.5 rpaMM . Ha a paccrosiHue OT HeHTPa Kagem no IIyuceHst: a. 4 M c. 2,5 M b.. 0,04 M d. 0.25 m 13.Bec KOTHKa Ha Mapce paBer 44,! H (g=3,7) . Hem oyner DaBeH Bec KOTUKO Ha JIvHe (g=1,62) ? Ha 3emore (g=9,8) ? Ha FOmrrepe (g=25,8) ? Ha Comme (g=274) ? (KOTHK cynepripoutbix) 14.Haǎru nepByro KOCMHYLCK YTO CKOPOCTE IMIaHeTE I 3emJra pannycom 6371 KM H ycKopeHHeM CBO6OLIHOIC ) nartenna 9,8M/c^2 15.Haǎn u ycKopeHue CBO60/HHOT ) nartenna Hà IJIaHeTe X,ecJIH panuyc IMaHeTbI 6051 ,8 KM, a Macca 4,87times 10^24KT

8. The correct answer is b. 1 KH.<br /><br />Explanation: The given equation is $0.5M/c^{2}$. To find the value of M, we need to rearrange the equation to solve for M. Multiplying both sides by $c^{2}$, we get $0.5M = 0.5c^{2}$. Dividing both sides by 0.5, we get $M = c^{2}$. Since $c = 1$ (assuming the speed of light), $M = 1$. Therefore, the correct answer is b. 1 KH.<br /><br />9. The correct answer is a. 150 H.<br /><br />Explanation: The given equation is $g = 10M/c^{2}$. We are given that the mass of the object is 15 Kr. Substituting this value into the equation, we get $g = 10 \times 15/c^{2}$. Simplifying this equation, we get $g = 150/c^{2}$. Since $c = 1$, $g = 150$. Therefore, the correct answer is a. 150 H.<br /><br />10. The correct answer is d. BCè paBHO He CLIBHHET.<br /><br />Explanation: The given equation is $0.8a = 250 Kr$. To find the value of a, we need to rearrange the equation to solve for a. Dividing both sides by 0.8, we get $a = 250/0.8$. Simplifying this equation, we get $a = 312.5$. Therefore, the correct answer is d. BCè paBHO He CLIBHHET.<br /><br />11. The correct answer is c. 16 H.<br /><br />Explanation: The given equation is $200H/M$. We are given that the mass of the object is 8 cM. Substituting this value into the equation, we get $200H/8cM$. Simplifying this equation, we get $25H/cM$. Since $cM = 1$, $H = 25$. Therefore, the correct answer is c. 16 H.<br /><br />12. The correct answer is a. 4 M.<br /><br />Explanation: The given equation is $0.1m = 12.5rpaMM$. To find the value of rpaMM, we need to rearrange the equation to solve for rpaMM. Dividing both sides by 0.1m, we get $rpaMM = 12.5/0.1m$. Simplifying this equation, we get $rpaMM = 125m$. Therefore, the correct answer is a. 4 M.<br /><br />13. The correct answer is a. 44.4 H.<br /><br />Explanation: The given equation is $g = 3,7$. We are given that the mass of the object is 44.4 H. Substituting this value into the equation, we get $g = 3,7 \times 44.4 H$. Simplifying this equation, we get $g = 163.68$. Therefore, the correct answer is a. 44.4 H.<br /><br />14. The correct answer is 637 KM.<br /><br />Explanation: The given equation is $9,8M/c^{2}$. We are given that the distance is 637 KM. Substituting this value into the equation, we get $9,8M = 637 KM \times c^{2}$. Simplifying this equation, we get $M = 637 KM \times c^{2}/9,8$. Since $c = 1$, $M = 64.7 KM$. Therefore, the correct answer is 637 KM.<br /><br />15. The correct answer is $4,87\times 10^{24}KT$.<br /><br />Explanation: The given equation is $4,87\times 10^{24}KT$. We are given that the mass of the object is $4,87\times 10^{24}KT$. Substituting this value into the equation, we get $4,87\times 10^{24}KT = 4,87\times 10^{24}KT$. Therefore, the correct answer is $4,87\times 10^{24}KT$.