In the laboratory workshop, the noise intensity level reached 80 dB. In order to reduce noise it was decided to cover the walls of this room with a sound -absorbing material that reduces the sound intensity by 1000 times, What level of noise intensity will be in this room after that?

The noise intensity level in decibels is a logarithmic measure, which means that each increase of 10 dB represents a tenfold increase in sound intensity. Therefore, to reduce the sound intensity by 1000 times, we need to decrease the noise level by 30 dB (since^(-3) = 10^(-30/10) = 10^(-3) = 30 dB).<br /><br />So, if the original noise level was 80 dB, after reducing the sound intensity by 30 dB, the new noise level will be 80 dB - 30 dB = 50 dB.