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The Stefan - Boltzmann law describes the power radiated from a black body: a) S=klnW b) varepsilon =(3)/(2)kT c) R=sigma T^4 d) E=hv Bbl6epure oAMH OTBeT: b) a) C) d)

Вопрос

The Stefan - Boltzmann law describes the power
radiated from a black body:
a) S=klnW
b) varepsilon =(3)/(2)kT
c) R=sigma T^4
d) E=hv
Bbl6epure oAMH OTBeT:
b)
a)
C)
d)

The Stefan - Boltzmann law describes the power radiated from a black body: a) S=klnW b) varepsilon =(3)/(2)kT c) R=sigma T^4 d) E=hv Bbl6epure oAMH OTBeT: b) a) C) d)

Решения

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мастер · Репетитор 5 лет

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The correct answer is c) $R=\sigma T^{4}$.<br /><br />The Stefan-Boltzmann law states that the total energy radiated per unit surface area of a black body is directly proportional to the fourth power of its absolute temperature. This can be expressed mathematically as:<br /><br />$R = \sigma T^4$<br /><br />where:<br />- $R$ is the total energy radiated per unit surface area (in watts per square meter, W/m²)<br />- $\sigma$ is the Stefan-Boltzmann constant, approximately equal to $5.67 \times 10^{-8}$ W/m²K⁴<br />- $T$ is the absolute temperature of the black body (in Kelvin, K)<br /><br />The other options are not correct:<br />a) $S=klnW$ is not the Stefan-Boltzmann law.<br />b) $\varepsilon =\frac {3}{2}kT$ is not the Stefan-Boltzmann law.<br />d) $E=hv$ is the Planck-Einstein relation, not the Stefan-Boltzmann law.
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