In the courae of the experiment, the properties of the material of a some body were investigated, as a result of which the average dengity and ite absolute error were obtained bar (rho )=1.90g/cm^3 Delta bar (rho )=0.0542ldots g/cm^3 Please select the correct record of the final result of this experiment rho =(1.90pm 0.05)g/cm^3 rho =1.9pm 0.05 rho =(2.0pm 0.1)g/cm rho =1.9pm 1.0 rho =(1.9pm 0.0542)g/cm^3 rho =1.90pm 0.05

The correct record of the final result of this experiment is $\rho =(1.90\pm 0.05)g/cm^{3}$.<br /><br />Explanation:<br />The average density of the material is given as $\bar{\rho}=1.90g/cm^{3}$, and the absolute error is given as $\Delta\bar{\rho}=0.0542g/cm^{3}$. The absolute error is typically rounded to one decimal place, so it is rounded to $0.05g/cm^{3}$. Therefore, the correct record of the final result is $\rho =(1.90\pm 0.05)g/cm^{3}$.