Вопрос
In the experiment , the motion of a body was investig ated, a s a result of which the average speed and its absolute error were obtained bar (V)=25.6m/s Delta bar (V)=0.1648025ldots m/s Please indicate the correct record of the final result of this experiment. V=(25.6+0.1)m/s V=(25.6pm 0.2)m/s V=(25.60pm 0.1)m/s V=(25.6pm 0.1)m/s
Решения
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The correct record of the final result of this experiment is:<br />$V=(25.60\pm 0.16)m/s$<br /><br />Explanation:<br />The average speed is given as $\bar{V}=25.6m/s$, and the absolute error is given as $\Delta \bar{V}=0.1648025\ldots m/s$. To record the final result, we need to round the absolute error to the appropriate number of significant figures.<br /><br />Since the average speed is given to two decimal places, we should round the absolute error to two decimal places as well. Therefore, the absolute error is rounded to $0.16m/s$.<br /><br />The final result is recorded as $V=(25.60\pm 0.16)m/s$, where the average speed is given to two decimal places and the absolute error is given to two decimal places as well.
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