Option 1 1. A ball weighing 250g fell to the stone floor at a speed of 3m/s and bounced up with the same modulo velocity. The duration of the ball'interaction with the floor is 0.1 seconds. a) What is the modulus of the momentum of the ball before hitting the floor? b) What is the modulo change in the momentum of the ball as a result of impact? b) What is the average pressure force of the ball on the floor during impact?

a) The modulus of the momentum of the ball before hitting the floor can be calculated using the formula:<br /><br />p = m * v<br /><br />where p is the momentum, m is the mass of the ball, and v is the velocity of the ball.<br /><br />Given that the mass of the ball is 250g (or 0.25 kg) and the velocity is 3 m/s, we can substitute these values into the formula:<br /><br />p = 0.25 kg * 3 m/s = 0.75 kg*m/s<br /><br />Therefore, the modulus of the momentum of the ball before hitting the floor is 0.75 kg*m/s.<br /><br />b) The modulo change in the momentum of the ball as a result of impact can be calculated by finding the difference between the momentum before and after the impact.<br /><br />Since the ball bounces back with the same modulo velocity, the momentum after the impact will have the same magnitude but opposite direction. Therefore, the change in momentum can be calculated as:<br /><br />Δp = p_after - p_before<br /><br />Since p_after = -p_before (opposite direction), we have:<br /><br />Δp = -p_before - p_before = -2 * p_before<br /><br />Substituting the value of p_before from part a), we get:<br /><br />Δp = -2 * 0.75 kg*m/s = -1.5 kg*m/s<br /><br />Therefore, the modulo change in the momentum of the ball as a result of impact is 1.5 kg*m/s.<br /><br />c) The average pressure force of the ball on the floor during impact can be calculated using the formula:<br /><br />F_avg = Δp / Δt<br /><br />where F_avg is the average pressure force, Δp is the change in momentum, and Δt is the duration of the impact.<br /><br />Given that the change in momentum is 1.5 kg*m/s and the duration of the impact is 0.1 seconds, we can substitute these values into the formula:<br /><br />F_avg = 1.5 kg*m/s / 0.1 s = 15 N<br /><br />Therefore, the average pressure force of the ball on the floor during impact is 15 N.