Merozos Mg+H_(2)SO_(4)=MgSO_(4)+H_(2)S+H_(2)O

The given chemical equation is:<br /><br />\[ \text{Mg} + \text{H}_2\text{SO}_4 \rightarrow \text{MgSO}_4 + \text{H}_2\text{S} + \text{H}_2\text{O} \]<br /><br />This equation represents the reaction between magnesium (Mg) and sulfuric acid (H₂SO₄) to produce magnesium sulfate (MgSO₄), hydrogen sulfide (H₂S), and water (H₂O).<br /><br />To balance this chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Let's start by counting the number of atoms of each element in the unbalanced equation:<br /><br />- Mg: 1 atom on the left, 1 atom on the right<br />- H: 2 atoms on the left, 3 atoms on the right<br />- S: 1 atom on the left, 1 atom on the right<br />- O: 4 atoms on the left, 5 atoms on the right<br /><br />We can see that the number of hydrogen and oxygen atoms are not balanced. To balance the equation, we need to adjust the coefficients (the numbers in front of the compounds).<br /><br />Let's start by balancing the hydrogen atoms. We have 2 hydrogen atoms on the left side and 3 on the right side. To balance the hydrogen atoms, we can put a coefficient of 2 in front of H₂S:<br /><br />\[ \text{Mg} + \text{H}_2\text{SO}_4 \rightarrow \text{MgSO}_4 + 2\text{H}_2\text{S} + \text{H}_2\text{O} \]<br /><br />Now, let's count the atoms again:<br /><br />- Mg: 1 atom on the left, 1 atom on the right<br />- H: 2 atoms on the left, 6 atoms on the right<br />- S: 1 atom on the left, 1 atom on the right<br />- O: 4 atoms on the left, 5 atoms on the right<br /><br />We still have an imbalance in the number of hydrogen and oxygen atoms. To balance the oxygen atoms, we can put a coefficient of 2 in front of H₂SO₄:<br /><br />\[ \text{Mg} + 2\text{H}_2\text{SO}_4 \rightarrow \text{MgSO}_4 + 2\text{H}_2\text{S} + \text{H}_2\text{O} \]<br /><br />Now, let's count the atoms again:<br /><br />- Mg: 1 atom on the left, 1 atom on the right<br />- H: 4 atoms on the left, 6 atoms on the right<br />- S: 2 atoms on the left, 1 atom on the right<br />- O: 8 atoms on the left, 5 atoms on the right<br /><br />We still have an imbalance in the number of sulfur and oxygen atoms. To balance the sulfur atoms, we can put a coefficient of 3 in front of H₂S:<br /><br />\[ \text{Mg} + 2\text{H}_2\text{SO}_4 \rightarrow \text{MgSO}_4 + 3\text{H}_2\text{S} + \text{H}_2\text{O} \]<br /><br />Now, let's count the atoms again:<br /><br />- Mg: 1 atom on the left, 1 atom on the right<br />- H: 4 atoms on the left, 6 atoms on the right<br />- S: 2 atoms on the left, 2 atoms on the right<br />- O: 8 atoms on the left, 8 atoms on the right<br /><br />Now, the equation is balanced. The balanced chemical equation is:<br /><br />\[ \text{Mg} + 2\text{H}_2\text{SO}_4 \rightarrow \text{MgSO}_4 + 3\text{H}_2\text{S} + \text{H}_2\text{O} \]