Bapnan TI 1. CreneHb , nMerorriem chop- My JIy H_(4)P_(2)O_(7) a) +7 6) +3 B) +5 r) -3

The correct answer is B) $+5$.<br /><br />In the compound $H_{4}P_{2}O_{7}$, the phosphorus (P) atom is bonded to four hydrogen (H) atoms and two oxygen (O) atoms. To determine the oxidation state of phosphorus, we need to consider the oxidation states of hydrogen and oxygen.<br /><br />The oxidation state of hydrogen is +1, and the oxidation state of oxygen is -2.<br /><br />Let's assign the oxidation state of phosphorus as x.<br /><br />The sum of the oxidation states in the compound must be zero. Therefore, we can set up the equation:<br /><br />4(+1) + 2x + 7(-2) = 0<br /><br />Simplifying the equation, we get:<br /><br />4 + 2x - 14 = 0<br /><br />2x - 10 = 0<br /><br />2x = 10<br /><br />x = 5<br /><br />Therefore, the oxidation state of phosphorus in $H_{4}P_{2}O_{7}$ is +5.