ovlution? or NaNO_(3) must be taken to prepare 300 ml of a 0.2M 2. For a complex compound [Ni(NH_(3))_(6)]SO_(4) indicate the outer and inner spheres, central ion, its charge and coordinate number, ligands and there dentation. Name the compound. 13. Finish and balance the redox-reaction CrCl_(3)+H_(2)O

1. To prepare a 0.2M solution of $NaNO_{3}$ in 300 ml, you need to calculate the amount of $NaNO_{3}$ required. The molarity (M) is defined as the number of moles of solute per liter of solution. So, you can use the formula:<br /><br />Molarity (M) = moles of solute / volume of solution in liters<br /><br />Given that the molarity is 0.2M and the volume is 300 ml (or 0.3 liters), you can rearrange the formula to solve for the moles of solute:<br /><br />moles of solute = Molarity (M) x volume of solution in liters<br /><br />moles of solute = 0.2M x 0.3L = 0.06 moles<br /><br />Now, you can calculate the mass of $NaNO_{3}$ required using the molar mass of $NaNO_{3}$, which is approximately 85.0 g/mol:<br /><br />mass of $NaNO_{3}$ = moles of solute x molar mass of $NaNO_{3}$<br />mass of $NaNO_{3}$ = 0.06 moles x 85.0 g/mol = 5.1 grams<br /><br />Therefore, you need to take 5.1 grams of $NaNO_{3}$ to prepare 300 ml of a 0.2M solution.<br /><br />2. In the complex compound $[Ni(NH_{3})_{6}]SO_{4}$, the outer sphere is the sulfate ion ($SO_{4}^{2-}$), and the inner sphere is the nickel ion ($Ni^{2+}$) coordinated with six ammonia molecules ($NH_{3}$). The central ion is nickel ($Ni^{2+}$), and its charge is +2. The coordinate number is 6, as there are six ammonia molecules coordinated with the nickel ion. The ligands are the ammonia molecules ($NH_{3}$). The compound is named Nickel(II) hexaammine sulfate.<br /><br />3. To balance the redox reaction $CrCl_{3}+H_{2}O$, you need to identify the oxidation states of the elements involved. In this case, chromium ($Cr$) has an oxidation state of +3 in $CrCl_{3}$ and +6 in $CrO_{3}$. The balanced equation for the reaction is:<br /><br />$2CrCl_{3}+3H_{2}O\rightarrow 2CrO_{3}+6HCl$