Вопрос
Molar solubility of Lead phosphate is related to its solubility product by equation: S=sqrt [5](K_(s)^0/108) S=sqrt [5](K_(s)^0/27) S=sqrt [3](K_(s)^0/3) S=sqrt [4](K_(s)^0/4) Molar solubility of Silver chloride is related to its solubility product by equation: S=sqrt (K_(s)^0) S=sqrt [3](K_(s)^0/3) S=sqrt [4](K_(s)^0/4)
Решения
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Антонина
эксперт · Репетитор 3 летЭкспертная проверка
Отвечать
The correct answer for the molar solubility of Lead phosphate is:<br />$S=\sqrt [5]{K_{s}^{0}/108}$<br /><br />The correct answer for the molar solubility of Silver chloride is:<br />$S=\sqrt {K_{s}^{0}}$
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