CH_(8)(CH_(2)-CH_(2))_(n)xrightarrow (Cracking)ldots +CH_(2)=CH-CH=CH_(2)+ldots

The correct answer is:<br /><br />$CH_{8}(CH_{2}-CH_{2})_{n}\xrightarrow {Cracking}C_{4}H_{10}+CH_{2}=CH-CH=CH_{2}$<br /><br />Explanation:<br />The given reaction represents the cracking process of a hydrocarbon compound. In this process, the hydrocarbon compound $CH_{8}(CH_{2}-CH_{2})_{n}$ is broken down into smaller hydrocarbon molecules.<br /><br />The product of the cracking process is 1-butene ($CH_{2}=CH-CH=CH_{2}$) and butane ($C_{4}H_{10}$). The cracking process involves the breaking of carbon-carbon bonds in the hydrocarbon compound, resulting in the formation of smaller hydrocarbon molecules.<br /><br />Therefore, the correct answer is $C_{4}H_{10}+CH_{2}=CH-CH=CH_{2}$.