1. For titration of 20.00 ml of the analyzed solution containing iron(III)salt, 18.50 ml of EDTA solution with a molar concentration of 0.02500mol/L and a correction factor of 0.9800 were spent . Calculate the weight of iron (in grams).

To calculate the weight of iron in the analyzed solution, we need to follow these steps:<br /><br />1. Calculate the moles of EDTA used in the titration.<br />2. Use the stoichiometry of the reaction between iron(III) salt and EDTA to find the moles of iron.<br />3. Convert the moles of iron to grams.<br /><br />Given information:<br />- Volume of the analyzed solution: 20.00 mL<br />- Volume of EDTA solution used: 18.50 mL<br />- Molar concentration of EDTA solution: 0.02500 mol/L<br />- Correction factor for EDTA: 0.9800<br /><br />Step 1: Calculate the moles of EDTA used in the titration.<br />Moles of EDTA = Volume of EDTA solution × Molar concentration of EDTA<br />Moles of EDTA = 18.50 mL × 0.02500 mol/L × 0.001 L/mL<br />Moles of EDTA = 0.0004625 mol<br /><br />Step 2: Use the stoichiometry of the reaction between iron(III) salt and EDTA to find the moles of iron.<br />The reaction between iron(III) salt and EDTA is a 1:1 molar ratio.<br />Moles of iron = Moles of EDTA<br />Moles of iron = 0.0004625 mol<br /><br />Step 3: Convert the moles of iron to grams.<br />Weight of iron = Moles of iron × Molar mass of iron<br />Weight of iron = 0.0004625 mol × 55.845 g/mol<br />Weight of iron = 0.0258 g<br /><br />Therefore, the weight of iron in the analyzed solution is 0.0258 grams.