Вопрос
10 romonorweckoro pana aJIKHHOB ABJI MOTC a 1) C_(2)H_(2) MC_(4)H_(6) 2) C_(6)H_(6) MC_(7)H_(8) 3) C_(5)H_(12)HC_(8)H_(18) 4) C_(3)H_(6) MC_(4)H_(8) 11. YcraHOBHTC COOTBeTCTBHe: KJIACC POPMYJI A 1) allkaHbl A) CH_(3)-CH_(2)-Cequiv C-CH(CH_(3))-CH_(3) 2) ankeHbl b) CH_(3)-CH(CH_(3))-CH_(2)-CH_(2)-CH_(3) 3) ankanueHb B) CH_(2)=CH-CH=CH-CH_(3) 4) aJIKHHbl D (-CH_(2)-CCl=CH-CH_(2))) 5) KayuykH 20 CH_(3)-C(CH_(3))=CH-CH(CH_(3))-CH_(3) E) (-CH_(2)-CH(CH_(3))-)n 12. Ha3BaHue yrneBo,10pona c popMynon CH_(2)=CH-C=CH-CH-CH_(3) downarrow CH_(3) CH_(2)-CH_(3) 1) 3-MeTHII-5-3THn-1,3-rekcallmen 2) 2-3THJ-4 -MeTHJI-3 ,5-rekca/meH 3) 3,5-AHMeTHJ-4.6-remanueH 4) 3,5-AHMeTHI-13-renranneH 13. KakHe u3 nap npuBeneHHbl ABJAIOTCA TOMO noramu? 1) CH_(2)=CH-CH_(2)-CH_(3) CH_(3)-CH=CH-CH_(3) 2) CH_(3)-CH=CH-CH_(2)-CH_(3) CH=C-CH-CHL-CH CHequiv C-CH-CH_(2)-CH_(3) CH_(3) 3) CH_(2)=CH-CH_(2)-CH_(3) H CH_(2)=CH-CH_(3) 4) CHequiv C-CH_(2)-CH_(3) M CH_(2)=CH-CH=CH-CH_(3)
Решения
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Чулпан
элита · Репетитор 8 летЭкспертная проверка
Отвечать
1) $C_{2}H_{2}\quad MC_{4}H_{6}$<br />2) $C_{6}H_{6}\quad MC_{7}H_{8}$<br />3) $C_{5}H_{12}HC_{8}H_{18}$<br />4) $C_{3}H_{6}\quad MC_{4}H_{8}$<br /><br />11. YcraHOBHTC COOTBeTCTBME:<br />1) aurkaHbl<br />A) $CH_{3}-CH_{2}-C\equiv C-CH(CH_{3})-CH_{3}$<br />2) ankeHbl<br />b) $CH_{3}-CH(CH_{3})-CH_{2}-CH_{2}-CH_{3}$<br />3) ankanueHb<br />B) $CH_{2}=CH-CH=CH-CH_{3}$<br />4) aJIKHHbl<br />$(-CH_{2}-CCl=CH-CH_{2}))$<br />5) KayuyKH<br />20 $CH_{3}-C(CH_{3})=CH-CH(CH_{3})-CH_{3}$<br />E) $(-CH_{2}-CH(CH_{3})-)n$<br /><br />12. Ha3BaHHe yrneBonopona c<br />$CH_{2}=CH-C=CH-CH-CH_{3}\\ \downarrow \\ CH_{3}\quad CH_{2}-CH_{3}$<br />1) 3-MeTHn-5-3THI -1,3-rekca<br />2) 2-3THJ-4-MeTHI-3.5<br />3) 3,5 -AHMeTHI-4,6 -remanneH<br />4) 3,5-AMMeTHA-13-remanueH<br /><br />13. KakHe u3 nap npHBeneHHbl ABJIAIOTCA TOMO noraMH?<br />1) $CH_{2}=CH-CH_{2}-CH_{3}$ ll $CH_{3}-CH=CH-CH_{3}$<br />2) $CH_{3}-CH=CH-CH_{2}-CH_{3}$ II CH=C-CH-CHL-CH<br />$CH\equiv C-CH-CH_{2}-CH_{3}\\ CH_{3}$<br />3) $CH_{2}=CH-CH_{2}-CH_{3}$ H $CH_{2}=CH-CH_{3}$<br />4) $CH\equiv C-CH_{2}-CH_{3}$ $M$ $CH_{2}=CH-CH=CH-CH_{3}$
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