a) Balance the reaction Fina ida an CrCl_(2)+H_(2)SO_(4)arrow Cr_(2)(SO_(4))_(2)+H_(2)SO_(3)+HCl+H_(2)O

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's start by counting the number of atoms for each element in the unbalanced equation:<br /><br />$CrCl_{2}+H_{2}SO_{4}\rightarrow Cr_{2}(SO_{4})_{2}+H_{2}SO_{3}+HCl+H_{2}O$<br /><br />On the left side:<br />- Chromium (Cr): 1 atom<br />- Chlorine (Cl): 2 atoms<br />- Hydrogen (H): 2 atoms<br />- Sulfur (S): 1 atom<br />- Oxygen (O): 4 atoms<br /><br />On the right side:<br />- Chromium (Cr): 2 atoms<br />- Chlorine (Cl): 1 atom<br />- Hydrogen (H): 5 atoms<br />- Sulfur (S): 3 atoms<br />- Oxygen (O): 11 atoms<br /><br />To balance the equation, we need to adjust the coefficients of the compounds. Let's start by balancing the chromium atoms by placing a coefficient of 2 in front of $CrCl_{2}$:<br /><br />$2CrCl_{2}+H_{2}SO_{4}\rightarrow Cr_{2}(SO_{4})_{2}+H_{2}SO_{3}+HCl+H_{2}O$<br /><br />Now, let's balance the chlorine atoms by placing a coefficient of 4 in front of $HCl$:<br /><br />$2CrCl_{2}+H_{2}SO_{4}\rightarrow Cr_{2}(SO_{4})_{2}+H_{2}SO_{3}+4HCl+H_{2}O$<br /><br />Next, let's balance the hydrogen atoms by placing a coefficient of 4 in front of $H_{2}SO_{4}$:<br /><br />$2CrCl_{2}+4H_{2}SO_{4}\rightarrow Cr_{2}(SO_{4})_{2}+H_{2}SO_{3}+4HCl+H_{2}O$<br /><br />Finally, let's balance the oxygen atoms by placing a coefficient of 3 in front of $H_{2}SO_{4}$:<br /><br />$2CrCl_{2}+3H_{2}SO_{4}\rightarrow Cr_{2}(SO_{4})_{2}+H_{2}SO_{3}+4HCl+H_{2}O$<br /><br />Now, let's count the atoms again to ensure they are balanced:<br /><br />On the left side:<br />- Chromium (Cr): 2 atoms<br />- Chlorine (Cl): 4 atoms<br />- Hydrogen (H): 12 atoms<br />- Sulfur (S): 3 atoms<br />- Oxygen (O): 12 atoms<br /><br />On the right side:<br />- Chromium (Cr): 2 atoms<br />- Chlorine (Cl): 4 atoms<br />- Hydrogen (H): 12 atoms<br />- Sulfur (S): 3 atoms<br />- Oxygen (O): 12 atoms<br /><br />The equation is now balanced. The balanced chemical equation is:<br /><br />$2CrCl_{2}+3H_{2}SO_{4}\rightarrow Cr_{2}(SO_{4})_{2}+H_{2}SO_{3}+4HCl+H_{2}O$