6. 0.5000 g of sodium chloride was dissolved in water and 200.0 ml of the solution was obtained. 20 .00 ml of this solution was titrated with 15.84 ml of silver nitrate solution . Calculate the molar concentration of the titrant solution.

To calculate the molar concentration of the titrant solution, we need to follow these steps:<br /><br />1. Calculate the moles of sodium chloride (NaCl) in the 20.00 ml solution.<br />2. Use the stoichiometry of the reaction between NaCl and silver nitrate (AgNO3) to find the moles of AgNO3.<br />3. Calculate the molar concentration of the AgNO3 solution.<br /><br />Step 1: Calculate the moles of NaCl in the 20.00 ml solution.<br />Moles of NaCl = (mass of NaCl) / (molar mass of NaCl)<br />Moles of NaCl = 0.5000 g / (58.44 g/mol)<br />Moles of NaCl = 0.00857 mol<br /><br />Step 2: Use the stoichiometry of the reaction between NaCl and AgNO3 to find the moles of AgNO3.<br />The balanced chemical equation for the reaction between NaCl and AgNO3 is:<br />NaCl + AgNO3 → AgCl + NaNO3<br />From the equation, we can see that 1 mole of NaCl reacts with 1 mole of AgNO3.<br />Therefore, the moles of AgNO3 = moles of NaCl<br />Moles of AgNO3 = 0.00857 mol<br /><br />Step 3: Calculate the molar concentration of the AgNO3 solution.<br />Molar concentration = moles of solute / volume of solution in liters<br />Molar concentration = 0.00857 mol / 0.020 L<br />Molar concentration = 0.429 mol/L<br /><br />Therefore, the molar concentration of the titrant solution (silver nitrate solution) is 0.429 mol/L.