Вопрос
6. 8.50 ml of a standardized 0.05120mol/L silver nitrate solution was used to titrate 10.00 ml of ammonium thiocyanate solution . Calculate the molar concentration of ammonium thiocyanate solution
Решения
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To calculate the molar concentration of the ammonium thiocyanate solution, we can use the concept of stoichiometry and the fact that the reaction between silver nitrate (AgNO₃) and ammonium thiocyanate (NH₄SCN) is a 1:1 molar ratio.<br /><br />The balanced chemical equation for the reaction is:<br />\[ \text{AgNO}_3 + \text{NH}_4\text{SCN} \rightarrow \text{AgSCN} + \text{NH}_4\text{NO}_3 \]<br /><br />Given:<br />- Volume of silver nitrate solution used: 8.50 mL<br />- Molarity of silver nitrate solution: 0.05120 mol/L<br />- Volume of ammonium thiocyanate solution: 10.00 mL<br /><br />First, calculate the number of moles of silver nitrate used in the titration:<br />\[ \text{Moles of AgNO}_3 = \text{Molarity} \times \text{Volume (in liters)} \]<br />\[ \text{Moles of AgNO}_3 = 0.05120 \, \text{mol/L} \times \frac{8.50 \, \text{mL}}{1000 \, \text{mL/L}} \]<br />\[ \text{Moles of AgNO}_3 = 0.05120 \, \text{mol/L} \times 0.00850 \, \text{L} \]<br />\[ \text{Moles of AgNO}_3 = 0.0004356 \, \text{mol} \]<br /><br />Since the reaction is 1:1, the moles of NH₄SCN will be the same as the moles of AgNO₃:<br />\[ \text{Moles of NH}_4\text{SCN} = 0.0004356 \, \text{mol} \]<br /><br />Now, calculate the molar concentration of the ammonium thiocyanate solution:<br />\[ \text{Molarity of NH}_4\text{SCN} = \frac{\text{Moles of NH}_4\text{SCN}}{\text{Volume of NH}_4\text{SCN solution (in liters)}} \]<br />\[ \text{Molarity of NH}_4\text{SCN} = \frac{0.0004356 \, \text{mol}}{10.00 \, \text{mL} / 1000 \, \text{mL/L}} \]<br />\[ \text{Molarity of NH}_4\text{SCN} = \frac{0.0004356 \, \text{mol}}{0.010 \, \text{L}} \]<br />\[ \text{Molarity of NH}_4\text{SCN} = 0.04356 \, \text{mol/L} \]<br /><br />Therefore, the molar concentration of the ammonium thiocyanate solution is \( 0.04356 \, \text{mol/L} \).
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