Вопрос
Cuvert Cu^2+(0,06H)Vert Au^3+(0,003M)vert Au
Решения
4.6251 голоса
Бронислава
элита · Репетитор 8 летЭкспертная проверка
Отвечать
This is a representation of a galvanic (or voltaic) cell, which is a type of electrochemical cell that generates electrical energy from spontaneous redox reactions. In this particular cell, copper (Cu) is the anode, where oxidation occurs, and gold (Au) is the cathode, where reduction occurs.<br /><br />The notation $Cu\vert Cu^{2+}(0,06H)\Vert Au^{3+}(0,003M)\vert Au$ can be broken down as follows:<br /><br />- $Cu$ represents the copper electrode.<br />- $Cu^{2+}(0,06H)$ represents the copper(II) ions in a 0.06 M solution.<br />- $\Vert$ represents the salt bridge or membrane that separates the two half-cells.<br />- $Au^{3+}(0,003M)$ represents the gold(III) ions in a 0.003 M solution.<br />- $Au$ represents the gold electrode.<br /><br />In this cell, the copper electrode undergoes oxidation, losing electrons to form copper(II) ions. The gold(III) ions in the solution gain these electrons, reducing to form gold metal. The salt bridge allows the flow of ions between the two half-cells, maintaining charge neutrality.<br /><br />The notation $(0,06H)$ and $(0,003M)$ represent the concentrations of the respective ions in the solutions. These values are important in determining the cell potential and the overall reaction.<br /><br />Overall, this galvanic cell can be represented by the following reaction:<br /><br />$Cu(s) + 2Au^{3+}(aq) \rightarrow Cu^{2+}(aq) + 2Au(s)$<br /><br />This reaction shows that copper metal reacts with gold(III) ions to form copper(II) ions and gold metal.
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