What volume of calcium chloride solution with a mass fraction of 22% and a density of 1.16g/ml is required to prepare 200 ml of a solution with a concentration of 0.1mol/I

To solve this problem, we need to find the volume of the calcium chloride solution with a mass fraction of 22% and a density of 1.16 g/ml that is required to prepare 200 ml of a solution with a concentration of 0.1 mol/L.<br /><br />Given information:<br />- Desired concentration of the final solution: 0.1 mol/L<br />- Volume of the final solution: 200 ml<br />- Mass fraction of the calcium chloride solution: 22%<br />- Density of the calcium chloride solution: 1.16 g/ml<br /><br />Step 1: Calculate the molar mass of calcium chloride (CaCl2).<br />Molar mass of CaCl2 = 40.08 g/mol (Ca) + 2 × 35.45 g/mol (Cl) = 110.98 g/mol<br /><br />Step 2: Calculate the mass of calcium chloride required for the final solution.<br />Mass of CaCl2 = Concentration × Volume × Molar mass<br />Mass of CaCl2 = 0.1 mol/L × 0.2 L × 110.98 g/mol = 22.196 g<br /><br />Step 3: Calculate the mass of the calcium chloride solution required.<br />Mass of calcium chloride solution = Mass of CaCl2 / Mass fraction<br />Mass of calcium chloride solution = 22.196 g / 0.22 = 100.9 g<br /><br />Step 4: Calculate the volume of the calcium chloride solution required.<br />Volume of calcium chloride solution = Mass of calcium chloride solution / Density<br />Volume of calcium chloride solution = 100.9 g / 1.16 g/ml = 86.8 ml<br /><br />Therefore, the volume of the calcium chloride solution with a mass fraction of 22% and a density of 1.16 g/ml that is required to prepare 200 ml of a solution with a concentration of 0.1 mol/L is 86.8 ml.