1. How many grams of NaNO_(3) must be taken to prepare 300 ml of a 0.2N solution? 2. For a complex compound [Ni(NH_(3))_(6)]SO_(4) indicate the outer and inner spheres, central ion, its charge and coordinate number, ligands and there dentation. Name the compound.

1. To prepare a 0.2N solution of NaNO3, we need to calculate the amount of NaNO3 required.<br /><br />Normality (N) is defined as the number of equivalents of solute per liter of solution. In this case,ity is 0.2N, which means there are 0.2 equivalents of NaNO3 per liter of solution.<br /><br />To find the amount of NaNO3 required, we can use the formula:<br /><br />Amount of solute (in grams) = Normality (N) x Volume (in liters) x Molar mass (in g/mol)<br /><br />Given:<br />Normality (N) = 0.2N<br />Volume (V) = 300 mL = 0.3 L<br />Molar mass of NaNO3 = 85.0 g/mol<br /><br />Substituting the values into the formula:<br /><br />Amount of NaNO3 = 0.2N x 0.3 L x 85.0 g/mol<br />Amount of NaNO3 = 5.1 grams<br /><br />Therefore, of NaNO3 must be taken to prepare 300 mL of a 0.2N solution.<br /><br />2. For the complex compound [Ni(NH3)6]SO4:<br /><br />Outer sphere: [Ni(NH3)6]^2+<br />Inner sphere: SO4^2-<br />Central ion: Ni^2+<br />Charge: +2<br />Coordinate number: 6<br />Ligands: NH3 (ammonia)<br /><br />The compound is named as Nickel(II) hexaammine sulfate.