Fevert Fe^3+(0,3H)Vert H_(2)SO_(4)(0,1M)vert H_(2)(Pt)

The correct answer is:<br /><br />$Fe\vert Fe^{3+}(0,3H)\Vert H_{2}SO_{4}(0,1M)\vert H_{2}(Pt)$<br /><br />This represents a galvanic cell where iron (Fe) is the anode, iron(III) ions (Fe^{3 are the cathode, sulfuric acid (H_{2}SO_{4}) is the electrolyte, and hydrogen gas (H_{2}) is produced at the cathode using a platinum (Pt) electrode.