9. Delta xrightarrow (HCl)x_(N)arrow x_(4)arrow a_(2)Cl_(2)xrightarrow (H_(2)Cle_(3))x_(3)

The given chemical reaction sequence is as follows:<br /><br />$\Delta \xrightarrow {HCl}x_{N}\rightarrow x_{4}\rightarrow a_{2}Cl_{2}\xrightarrow {H_{2}Cle_{3}}x_{3}$<br /><br />To determine the final product $x_{3}$, we need to analyze each step of the reaction.<br /><br />1. The first step involves heating ($\Delta$) and reacting with hydrochloric acid (HCl). This suggests a decomposition reaction where a compound breaks down into simpler substances. Let's assume the initial compound is $x_{N}$.<br /><br />2. The second step involves the formation of $x_{4}$ from $x_{N}$. This could be a substitution or addition reaction.<br /><br />3. The third step involves the reaction of $a_{2}Cl_{2}$ with $H_{2}Cle_{3}$. This suggests a substitution reaction where $H_{2}Cle_{3}$ replaces the chlorine atom in $a_{2}Cl_{2}$.<br /><br />4. The final step involves the formation of $x_{3}$ from the previous reaction.<br /><br />Based on the given information, we can infer that $x_{N}$ is a compound that decomposes upon heating to form $x_{4}$. $x_{4}$ then reacts with $a_{2}Cl_{2}$ to form $x_{3}$.<br /><br />To determine the exact identity of $x_{3}$, we need more information about the specific compounds involved in each step. However, based on the given sequence, we can conclude that $x_{3}$ is the final product formed after the reaction of $a_{2}Cl_{2}$ with $H_{2}Cle_{3}$.<br /><br />Therefore, the final product $x_{3}$ is the compound formed after the reaction of $a_{2}Cl_{2}$ with $H_{2}Cle_{3}$.