Na^+11) 1_(11)Na2overline (e),8overline (e),1overline (e).

It looks like you're presenting the electron configuration of a sodium ion (Na⁺). Let's break it down:<br /><br />1. **Neutral Sodium Atom (Na):**<br /> - Atomic number: 11<br /> - Electron configuration: \(1s^2 2s^2 2p^6 3s^1\)<br /><br />2. **Sodium Ion (Na⁺):**<br /> - Sodium loses one electron to achieve a stable electron configuration similar to neon (Ne).<br /> - Electron configuration of Na⁺: \(1s^2 2s^2 2p^6\)<br /><br />So, the electron configuration of the sodium ion (Na⁺) is:<br />\[ 1s^2 2s^2 2p^6 \]<br /><br />This configuration shows that the sodium ion has lost its one valence electron, resulting in a stable noble gas configuration.