mathrm(KOH)+mathrm(HNO)_(3)=mathrm(KNO)_(3)+mathrm(H)_(2) mathrm(O)-

The given chemical equation is:<br /><br />\[ \mathrm{KOH} + \mathrm{HNO}_{3} = \mathrm{KNO}_{3} + \mathrm{H}_{2}\mathrm{O} \]<br /><br />This equation represents the reaction between potassium hydroxide (KOH) and nitric acid (HNO₃) to form potassium nitrate (KNO₃) and water (H₂O).<br /><br />To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's check the balance:<br /><br />- Potassium (K): 1 atom on both sides<br />- Oxygen (O): 3 atoms in HNO₃ and 1 atom in KOH on the left side, and 3 atoms in KNO₃ and 1 atom in H₂O on the right side<br />- Hydrogen (H): 1 atom in KOH and 1 atom in HNO₃ on the left side, and 2 atoms in H₂O on the right side<br />- Nitrogen (N): 1 atom in HNO₃ on the left side and 1 atom in KNO₃ on the right side<br /><br />The equation is already balanced as written. Therefore, the balanced chemical equation is:<br /><br />\[ \mathrm{KOH} + \mathrm{HNO}_{3} = \mathrm{KNO}_{3} + \mathrm{H}_{2}\mathrm{O} \]<br /><br />This reaction is an example of an acid-base neutralization reaction, where an acid (HNO₃) reacts with a base (KOH) to produce a salt (KNO₃) and water (H₂O).