2) The standard electrode potential for tin Sn^2+(aq)+2e^-leftharpoons Sn(s) is -0.138V vs. the standard hydrogen electrode (SHE). What is the value of this standard electrode potential vs. the following: (a) the saturated calomel reference electrode? (b) the Ag/AgCl (saturated) reference electrode? (c) the Cu/CuSO_(4) (saturated) reference electrode?

To find the standard electrode potential of tin ($Sn^{2+}/Sn$) vs. other reference electrodes, we need to use the standard electrode potential of the given reference electrode and the standard electrode potential of the tin electrode relative to the standard hydrogen electrode (SHE).<br /><br />(a) Saturated calomel reference electrode:<br />The standard electrode potential of the saturated calomel reference electrode is $-0.244V$ vs. SHE. Therefore, the standard electrode potential of tin ($Sn^{2+}/Sn$) vs. the saturated calomel reference electrode can be calculated as follows:<br /><br />$E_{Sn^{2+}/Sn}^{0} - E_{SCE}^{0} = -0.138V - (-0.244V) = 0.106V$<br /><br />Therefore, the standard electrode potential of tin ($Sn^{2+}/Sn$) vs. the saturated calomel reference electrode is $0.106V$.<br /><br />(b) $Ag/AgCl$ (saturated) reference electrode:<br />The standard electrode potential of the $Ag/AgCl$ (saturated) reference electrode is $+0.197V$ vs. SHE. Therefore, the standard electrode potential of tin ($Sn^{2+}/Sn$) vs. the $Ag/AgCl$ (saturated) reference electrode can be calculated as follows:<br /><br />$E_{Sn^{2+}/Sn}^{0} - E_{Ag/AgCl}^{0} = -0.138V - (+0.197V) = -0.335V$<br /><br />Therefore, the standard electrode potential of tin ($Sn^{2+}/Sn$) vs. the $Ag/AgCl$ (saturated) reference electrode is $-0.335V$.<br /><br />(c) $Cu/CuSO_{4}$ (saturated) reference electrode:<br />The standard electrode potential of the $Cu/CuSO_{4}$ (saturated) reference electrode is $+0.337V$ vs. SHE. Therefore, the standard electrode potential of tin ($Sn^{2+}/Sn$) vs. the $Cu/CuSO_{4}$ (saturated) reference electrode can be calculated as follows:<br /><br />$E_{Sn^{2+}/Sn}^{0} - E_{Cu/CuSO_{4}}^{0} = -0.138V - (+0.337V) = -0.475V$<br /><br />Therefore, the standard electrode potential of tin ($Sn^{2+}/Sn$) vs. the $Cu/CuSO_{4}$ (saturated) reference electrode is $-0.475V$.