CuCl_(3)+Mn=MnCl_(2)+Cu , Fe_(2)O_(3)+CO=Fe+CO_(2) CrO_(3)=Cr_(2)O_(3)+O_(2) Ca(OH)_(2)+H_(3)PO_(4)=Ca_(3)(PO_(4))_(2)+H_(2)O

Let's balance each chemical equation step by step:<br /><br />1. $CuCl_{3}+Mn=MnCl_{2}+Cu$<br /><br />To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Balanced equation: $2CuCl_{3}+3Mn=3MnCl_{2}+2Cu$<br /><br />2. $Fe_{2}O_{3}+CO=Fe+CO_{2}$<br /><br />To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Balanced equation: $Fe_{2}O_{3}+3CO=2Fe+3CO_{2}$<br /><br />3. $CrO_{3}=Cr_{2}O_{3}+O_{2}$<br /><br />To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Balanced equation: $4CrO_{3}=2Cr_{2}O_{3}+3O_{2}$<br /><br />4. $Ca(OH)_{2}+H_{3}PO_{4}=Ca_{3}(PO_{4})_{2}+H_{2}O$<br /><br />To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Balanced equation: $3Ca(OH)_{2}+2H_{3}PO_{4}=Ca_{3}(PO_{4})_{2}+6H_{2}O$