1. For titration of 20.00 ml of the analyzed solution containing iron (III) salt. 18.50 ml of EDTA solution with a molar concentration of 0.02500 mol/L and a correction I factor of 0.9800 were spent. Calculate the weight of iron (in grams).

To calculate the weight of iron in the analyzed solution, we need to follow these1. Calculate the moles of EDTA used in the titration.<br />2. Determine the moles of iron (III) salt in the analyzed solution.<br />3. Convert the moles of iron (III) salt to grams.<br /><br />Step 1: Calculate the moles of EDTA used in the titration.<br /><br />Given:<br />Volume of EDTA solution used = 18.50 ml<br />Molar concentration of EDTA solution = 0.02500 mol/L<br />Correction factor of EDTA solution = 0.9800<br /><br />First, we need to convert the volume of EDTA solution from ml to L:<br />Volume of EDTA solution in L = 18.50 ml / 1000 = 0.01850 L<br /><br />Now, we can calculate the moles of EDTA used in the titration:<br />Moles of EDTA = Molar concentration of EDTA solution × Volume of EDTA solution in L<br />Moles of EDTA = 0.02500 mol/L × 0.01850 L<br />Moles of EDTA = 0.0004625 mol<br /><br />Step 2: Determine the moles of iron (III) salt in the analyzed solution.<br /><br />The reaction between EDTA and iron (III) salt is a 1:1 molar ratio. Therefore, the moles (III) salt in the analyzed solution will be equal to the moles of EDTA used in the titration:<br />Moles of iron (III) salt = Moles of EDTA<br />Moles of iron (III) salt = 0.0004625 mol<br /><br />Step 3: Convert the moles of iron (III) salt to grams.<br /><br />The molar mass of iron (III) salt (FeCl3) is 162.20 g/mol.<br /><br />Now, we can calculate the weight of iron in the analyzed solution:<br />Weight of iron = Moles of iron (III) salt × Molar mass of iron (III) salt<br />Weight of iron = 0.0004625 mol × 162.20 g/mol<br />Weight of iron = 0.0748 g<br /><br />Therefore, the weight of iron in the analyzed solution is 0.0748 grams.