- a State in sices for calculating comacitance of a transmission lin." b. Electric generated by installing a hydraulic turbine site i20m! free surface of a large vate:reservoir that call supply water at rate of 40 koys sicacily Determine the power seneration poiential. (5 marks) c. A thermal power station has the following data : his come proming in 1978. She checks her email efficiency 00% Coal consumption 0 . 9 ke/kWh : Cost of I ton of coal Determine: (5 marks) Thermal efficiency Coal bill per annum (7 marks) )crive the explession for calculating the inductance of a three-phase line. ()12.1.km overhead transmission line supplies 1000k Nat 11 KV 08 power factor agains the line resistance is 0.03 ohms and line inductance is 007 mill per oh:so ocrkin Calcu:aic the sending end voltage, the regulation and efficiency of the transmissioil line. (7 marks)
- (a) A clerk pushes a filing cabinet , whose mass m is 85 kg, at a constant speed across a tiled floor for a distance d of 3.1 m. the coefficient of friction u_(k) between the bottom of the cabinet and the carpet is 0.22.
- (iii) How much work does the frictional force do on the cabinet? (2 marks) (iv) How much work does the mg and N do on the cabinet? ( 2 marks) (v) What is the total work done on the cabinet by all the forces that act on it? (2 marks) (b) A crate whose mass m is 15 kg is pulled a distance d (=5.7m) up a frictionless ramp to a height h of 2.5 m. (i) What Force F must the winch cable exert? (3 marks) (ii)How much work is done by the force F? (3 marks) (iii) How much work would be required to lift the crate vertically upward, through the height h?
- Q2 (a) A clerk pushes a filing cabinet, whose mass m is 85 kg, at a constant speed across a tiled floor for a distance d of 3 .1 m. the coefficient of friction u_(k) between the bottom of the cabinet and the carpet is 0.22. (i) Identify the forces that act on the cabinet and calculate their
- KOMMUECTBEHHOTO OITPE/LE/TEHUS CYECT AHLIUU MbILLIbAKA TPMOKCH/1A OKO/10 40 Mr (TO4HA&H ABECKA) CY5CTAHI luu PACTBOPAHOT B CMECI 10 M/T BOAbI V 10 M/ 2 M PACTBOPATV APOKCU/JA HATPU 9. TIPMEABJIAHOT 10 M/T XJTOPU CTOBOROPOAHON KUCHOTbI PA3BELIEHHOU 7,3% V13TH ATPUA TULIPOKAPEOHAT A, TIEPEMELIJIBAIOT. TIPM5ABJIAHOT 1 MJT KPAXMAJTA PACTBOPA 1% V TUTPYHOT 0,05 M PACTBOPOM HOAA. ITAPA/TITE/IbHO ITPOBOART KOHTPO/IbHbIU OIIbIT. YPABH IEHVIE AJTA PACHETA COAEPX AHUA MbILLIbAKA TPMOKCH/JA B CYECTAHLINU, % Bbl6epnTe OAMH OTBeT: a X% =((V_(T1)-V_(T2))cdot Kcdot T)/(a)cdot 100% b X% =((V_(00)-V_(X,0))cdot Kcdot T)/(a)cdot 100% ) C. X% =((V_(KO)-V_(000))cdot Kcdot T)/(a)cdot 100% d. X% =(Vcdot kcdot T)/(a)cdot 100% (C)
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