- Useful constants Acceleration due to gravity=9.8m/s^2 Universal gravitational constant G=6.673times 10^-11Nm^2kg^-2 QUESTION ONE (30MARKS) a) Write down the units and dimensions of kinetic energy. (2mks) b) State Newtons second law of motion. (2mks) c) Abody A of mass 5kg moving with a velocity of 3mls collides head-on with another body B of mass 4kg moving in the opposite direction at 6mls. If after the collision the bodies move together, calculate the common velocity. (3mks) d) Two forces (500N,80^circ )and(600N,150^circ ) act at 9 point,determine the resultant force. (4mks) e) Distinguish between elastic and inelastic collision. (2mks) f) Explain why a body moving round a circular path at uniform tangential velocity is said to be accelerating. (2mks) g) Find the angular frequency of a car that moves at uniform velocity of 2mls in a circular path of 0.4m radius. Take pi =3.142 (4mks) Page 1 of 4 h) A car drives off the edge of a cliff that is 54m high. A police officer at the scene of accident notes that the point of impact is 150m from the base of the cliff. How fast was the car travelling when it went off the cliff? (5mks) i) Given that overrightarrow (n)=3i-2j-1k overrightarrow (0)=2j-4i+3k Find overrightarrow (n)cdot overrightarrow (0) (3mks) j) A stone of mass 0.6kg attached to a string of length 0.5m, is whirled in a horizontal circle at a constant speed. If the maximum tension in the string is 30N before it breaks. Calculate the maximum speed of the stone. (3mks) a) (i) What is moment of intertia (1mk) (ii) A fly wheel of radius 0.75m has a mass of 250kg and a torque of 30N acts on it. Calculate its moment of inertia and angular accelerated. (6mks) b) For a uniformly accelerated body derive the equation for the kinetic energy gained. (6mks) c) For the gravitational intensity g show that the period T is given by T=2pi sqrt (4g) (7mks) QUESTION THREE (20 MARKS) a) A metal rod of radius 4.0mm and length 90cm is held to a clamp.A force of magnitude 90,000N is applied perpendicularly to the end face at the other end. If the elongation is 2.0mm ,determine the Youngs modulus of elasticity of the rod.
- 6. KHATa Ma ccoπ 300 T JIe HT Hà CTOJIe BbICOTO# 90 ee mor ennua JIbHax 9Heprns? 1) 2,7cdot 10^-2AxK 2) 2,7Ax 2,7cdot 10^2Ax 4) 27cdot 10^3 Mx
- 6. KHura mac coǎ 300 T JIeN UT Hà CTO JIe BbICOTO#90 cm yeary pasaa ee una JIbHRA 9H eorus? 1) 2,7cdot 10^-2Ak 2) 2,7Ax 3) 2,7cdot 10^2Ak 4) 27cdot 10^3Am
- (4) [ N=1000 mathrm(~mm) U=500 mathrm(p) C_(e)=400 mathrm(p) B-? C_(05 y)-? W-80 %-? V-? N_(k p)-? ] papuk 8 / y^5 nocomponto
- 3 Dano: [ S_(0)=20 mathrm(~m) / mathrm(c) P=50.411 h=60 mathrm(~m) h_(0)-? ]
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