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THE STUDENT ANSWERS 4 QUESTIONS DURING THE EXAM . ASSUMING THAT ALL ANSWERS ; ARE INDEPENDENT EVENTS, THE PROBABILITY OF AN EVENT CONSISTING THAT NOT LESS THEN THREE CORRECT ANSWERS WILL BE GIVEN CAN BE CALCU LATED AS Select one: P(A)=P_(4)(2)+P_(4)(3)+P_(4)(4) P(A)=P_(4)(4) P(A)=P_(4)(0)+P_(4)(1)+P_(4)(2) P(A)=P_(4)(3) P(A)=P_(4)(3)+P_(4)(4)

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THE STUDENT ANSWERS 4 QUESTIONS DURING THE EXAM . ASSUMING THAT ALL ANSWERS ; ARE INDEPENDENT EVENTS, THE PROBABILITY OF AN EVENT CONSISTING THAT NOT LESS THEN THREE CORRECT ANSWERS WILL BE GIVEN CAN BE CALCU LATED AS Select one: P(A)=P_(4)(2)+P_(4)(3)+P_(4)(4) P(A)=P_(4)(4) P(A)=P_(4)(0)+P_(4)(1)+P_(4)(2) P(A)=P_(4)(3) P(A)=P_(4)(3)+P_(4)(4)

THE STUDENT ANSWERS 4 QUESTIONS DURING THE EXAM . ASSUMING THAT ALL ANSWERS ; ARE INDEPENDENT EVENTS, THE PROBABILITY OF AN EVENT CONSISTING THAT NOT LESS THEN THREE CORRECT ANSWERS WILL BE GIVEN CAN BE CALCU LATED AS Select one: P(A)=P_(4)(2)+P_(4)(3)+P_(4)(4) P(A)=P_(4)(4) P(A)=P_(4)(0)+P_(4)(1)+P_(4)(2) P(A)=P_(4)(3) P(A)=P_(4)(3)+P_(4)(4)

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The correct answer is: $P(A)=P_{4}(3)+P_{4}(4)$<br /><br />Explanation: The probability of an event consisting of not less than three correct answers can be calculated by adding the probabilities of getting exactly three correct answers and getting exactly four correct answers. This is represented by the expression $P(A)=P_{4}(3)+P_{4}(4)$.
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