THERE ARE 3 WHITE AND 2 BLACK BALLS IN A BO X. ONE BALL . HAS BEEN TAKEN FROM THE BOX AND THEN I ANOTHER ONE. WHAT IS THE PROBABILITY F OR THE FIRST BALL WILL BEING WHITE AND SECOND ONE - BLACK? Select one: 3/5 3/10 1/2 6/25

To solve this problem, we need to calculate the probability of drawing a white ball first and then a black ball.<br /><br />Step 1: Calculate the probability of drawing a white ball first.<br />There are 3 white balls and 2 black balls in the box, making a total of 5 balls. The probability of drawing a white ball first is 3/5.<br /><br />Step 2: Calculate the probability of drawing a black ball second.<br />After drawing a white ball first, there are now 4 balls left in the box, with 2 black balls remaining. The probability of drawing a black ball second is 2/4 or 1/2.<br /><br />Step 3: Calculate the probability of both events happening.<br />To find the probability of both events happening, we multiply the probabilities of each event. So, the probability of drawing a white ball first and then a black ball is (3/5) * (1/2) = 3/10.<br /><br />Therefore, the correct answer is $3/10$.