HaHa do 3x^8+7x+8 Bbluncllu ee f'(x)=square xsquare +square

To find the derivative of the function $f(x) = 3x^8 + 7x + 8$, we need to apply the power rule for differentiation.<br /><br />The power rule states that the derivative of $x^n$ is $nx^{n-1}$.<br /><br />Let's differentiate each term of the function:<br /><br />1. The derivative of $3x^8$ is $24x^7$.<br />2. The derivative of $7x$ is $7$.<br />3. The derivative of the constant term $8$ is $0$.<br /><br />Putting it all together, we have:<br /><br />$f'(x) = 24x^7 + 7$<br /><br />So, the derivative of the function $f(x) = 3x^8 + 7x + 8$ is $f'(x) = 24x^7 + 7$.