Bblpa xeHu A. (640+310):50-13 (5cdot 17-1):7 (269-167):6+69

Let's solve each expression step by step:<br /><br />1. \((640+310):50-13\)<br /><br /> First, perform the addition inside the parentheses:<br /> \[<br /> 640 + 310 = 950<br /> \]<br /><br /> Then, divide by 50:<br /> \[<br /> 950 \div 50 = 19<br /> \]<br /><br /> Finally, subtract 13:<br /> \[<br /> 19 - 13 = 6<br /> \]<br /><br /> So, the result is \(6\).<br /><br />2. \((5 \cdot 17 - 1):7\)<br /><br /> First, perform the multiplication:<br /> \[<br /> 5 \cdot 17 = 85<br /> \]<br /><br /> Then, subtract 1:<br /> \[<br /> 85 - 1 = 84<br /> \]<br /><br /> Finally, divide by 7:<br /> \[<br /> 84 \div 7 = 12<br /> \]<br /><br /> So, the result is \(12\).<br /><br />3. \((269 - 167):6 + 69\)<br /><br /> First, perform the subtraction inside the parentheses:<br /> \[<br /> 269 - 167 = 102<br /> \]<br /><br /> Then, divide by 6:<br /> \[<br /> 102 \div 6 = 17<br /> \]<br /><br /> Finally, add 69:<br /> \[<br /> 17 + 69 = 86<br /> \]<br /><br /> So, the result is \(86\).<br /><br />To summarize:<br />1. \((640+310):50-13 = 6\)<br />2. \((5 \cdot 17 - 1):7 = 12\)<br />3. \((269 - 167):6 + 69 = 86\)