L, E, F, J, R, B & 2 & 3 & 1 & 7 & & 25 missing frequencies firection of variation e. pus dian and mode tritle deviation the MJ, GM and HN? nic mean of the following grouped data 80-100 & 100-120 38 & 45

To find the mean of the given grouped data, we need to calculate the midpoints of each class interval and then use the formula for the mean of grouped data.<br /><br />Step 1: Calculate the midpoints of each class interval.<br />Midpoint = (Lower limit + Upper limit) / 2<br />For the first class interval, 80-100, the midpoint is (80 + 100) / 2 = 90.<br />For the second class interval, 100-120, the midpoint is (100 + 120) / 2 = 110.<br /><br />Step 2: Multiply the midpoint of each class interval by the frequency of that class.<br />For the first class interval, 80-100, the product is 90 * 38 = 3420.<br />For the second class interval, 100-120, the product is 110 * 45 = 4950.<br /><br />Step 3: Sum up the products obtained in step 2.<br />Sum of products = 3420 + 4950 = 8370.<br /><br />Step 4: Calculate the total frequency.<br />Total frequency = 38 + 45 = 83.<br /><br />Step 5: Calculate the mean of the grouped data.<br />Mean = Sum of products / Total frequency<br />Mean = 8370 / 83 ≈ 101.08.<br /><br />Therefore, the mean of the given grouped data is approximately 101.08.